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[主观题]
证明:若函数f(x,y)在开区域G对变量x连续,对变量y满足利普希茨条件,即有|f(x,y1)-f(x,y2
证明:若函数f(x,y)在开区域G对变量x连续,对变量y满足利普希茨条件,即有|f(x,y1)-f(x,y2
证明:若函数f(x,y)在开区域G对变量x连续,对变量y满足利普希茨条件,即有|f(x,y1)-f(x,y2)|≤L|y1-y2|,
其中L是常数,则函数f(x,y)在G连续.
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