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[主观题]

There (1)_____ not one type of reading but several according to your reasons for reading.

There (1)_____ not one type of reading but several according to your reasons for reading. To read carefully, you have to (2)_____ your reading speed and technique (3)_____ your aim (4)_____ reading. Skimming is a technique necessary for quick and efficient reading.

When skimming, you (5)_____ the reading (6)_____ quickly in order to get the (7)_____ of it, to know how it is organized, (8)_____ an idea of the tone or the intention of the writer. Skimming is (9)_____ an activity which (10)_____ an overall view of the text and (11)_____ a definite reading competence.

Skimming doesn't need reading all the material, but it doesn't mean that it is an (12)_____ skill for the lazy, because it need a high degree of alertness and concentration.

When you read, you usually start with (13)_____ understanding and move towards detailed understanding rather than working the other way round. But (14)_____ is also used after you have already carefully studied and you need to (15)_____ the major ideas and concepts.

In order to be able to skim quickly and (16)_____ through a text, you should know where to look for what you want. In preview skimming you read the introductory information, the headings and subheadings, and the summary, if one is provided. (17)_____ this skimming, decide whether to read the material more thoroughly, and select the appropriate speed (18)_____ you read.

The same procedure (19)_____ for preview skimming could also be used to get an overview. Another method would be to read only key words. This is done by omitting the unnecessary words, phrases, and sentences.

In order to skim efficiently and fulfill your purpose, (20)_____ practice is necessary.

A.is

B.are

C.was

D.were

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更多“There (1)_____ not one type of reading but several according to your reasons for reading.”相关的问题

第1题

单链表和顺序表他们查找的时间复杂度是()

A.O(n)O(n)

B.O(n)O(1)

C.O(1)O(n)

D.O(1)O(1)

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第2题

求循环链表中当前结点的后继和前驱的时间复杂度分别是()。

A.O(n)和O(1)

B.O(1)和O(1)

C.O(1)和O(n)

D.O(n)和O(n)

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第3题

·— —·()

A.P

B.O

C.1

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第4题

计算tan20o+tan25o+tan20 o tan25 o =()

A.1

B.-1

C.根号3

D.3分之根号3

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第5题

下列程序段的时间复杂度为()。x = n; /*n > 1*/y = 0;while(x >= (y + 1) * (y + 1))y = y + 1

A.O(n)

B.O(n½)

C.O(1)

D.O(n2)

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第6题

可以诊断伤寒的是()

A."O"抗体>1:160,"H"抗体>1:160

B."O"抗体>1:80,"H"抗体>1:160

C."O"抗体>1:40,"H"抗体>1:80

D."O"抗体>1:80,"H"抗体>1:80

E."O"抗体>1:160,"H"抗体>1:80

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第7题

求单链表中当前结点的后继和前趋的时间复杂度分别是()。

A.O(n)和O(1)

B.O(1)和O(1)

C.O(1)和O(n)

D.O(n)和O(n)

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第8题

下列程序的空间复杂度是()。for(i=1;i<=n;++i){for(j=1;j<=m;++j){c[i][j]=0;}}

A.O(m*n)

B.O(m+n)

C.O(m-n)

D.O(m/n)

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第9题

下面程序的时间复杂性的量级为()。下面程序的时间复杂性的量级为()。

A.O(1)

B.O(2n)

C.O(n)

D.O(n/2)

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第10题

肥达反应有诊断价值的抗体效价,通常是(1.0)()

A.O凝集价≥1:40,H凝集价≥1:40

B.O凝集价≥1:80.H凝集价≥1:160

C.O凝集价>1:40,H凝集价≥1:160

D.O凝集价≥1:160,H凝集价≥1:80

E.O凝集价≥1:80.H凝集价≥1:80

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第11题

$f(x)=xln(1+x)$,则$f’(0)$=()

A.$O$

B.$1$

C.$-1$

D.$2$

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